A solid, pure substance containing just carbon and hydrogen is found to contain 23.6g of carbon and 3.45 g of hydrogen. How many grams of carbon will be in a 6.45 g sample of the solid?

Grams of Carbon =126g

Solution: n(Fe2O3)=25.0mol n(Fe0)-? 1. For calculation n(Fe) we need to calculate m(Fe2O3): Mr(Fe2O3)=55.85*2+16*3=159.6(g/mol) n=m/Mr; hereof m(Fe2O3)=n*Mr=159.6(g/mol)*25mol=3990g 2. Compose proportion: 3990(g) it is 159.6 X(g) it is 55.85*2 Where X is the total...

c = Q / m * ∆T ∆T = T2 – T1 T2 = t2 + 273.15 = 154.8 °C+ 273.15 = 427.95 K T1 = t1 + 273.15 =...

CxHy w(C) = 4.1315 g / (4.1315 g + 0.8685 g) = 0.8263 w(H) = 0.8685 g / (4.1315 g + 0.8685 g) = 0.1737 x : y = 0.8263/12,0107...

mass (carbon) = 4.6 g

CH4 12------4X--------42X= 42 x 12/4= 126 g of carbon

Molecular weight of iron 55.84 gm10 gm contain 0.179 mol of iron same number of moles contain same number of atom irrespective of identity of atom0.179 mol of Aluminium will...

Solution.n(C) = 0.232 molesn (CH3COOH) = 0.116 molesm (CH3COOH) = 0.116*60 = 6.97 gAnswer. 6.97 g

35g N, 5.05g h, 60.0g 02..5.05÷100.05=0.05047476260.005047...x137=6.9156.915g of hydrogen in 137 g sample

Solution:76g / 1g/mol=76 mol of H476mol / 4 = 19 mol of C19 mol * 12 g/mol=228g of CAnswer:228 grams.