What is the mass in grams of 1.90x10^24 atoms of scandium

Md Ariful Islam

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m (Sc) = n×M, where n is amount of substance, mole; M is molar mass, g/ mole n (Sc) = N/Na, N is number of atoms, Na is Avogadro constant n = 1.90×10^24/6.02×10^23 = 3.2 mole m = 3.2 × 45 = 144 g
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