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A certain compound was found to contain 54.0 g of carbon and 10.5 grams of hydrogen Its relative molecular mass is 86.0 Find the empirical and the molecular formulas
n(C)=54/12=4,5moln(H)=10.5/1=10.5molC:H=4,5:10,5=1:2CH2M(CH2)=14g/mol86/14=6Answer: C6H14
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if the heat of combustion for a specific compound is -1130.0 kJ/mol and its molar mass is 35.99 g/mol how many grams of this compound must you burn to release 134.30 kJ of the heat?
134.30(mol/1130kJ)(35.99/mol)= 4.2774g
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Compound <i>X</i> has a molar mass of 135.12·gmol−1 and the following composition: element/mass carbon: 44.44% hydrogen: 3.73% oxygen: 51.83% Write the molecular formula of <i>X</i>
v(C)=135/44.44=3molv(H)=135/3.73=36molv(O)=135/51.83=3molC3H36O3
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Determine the empirical and molecular formula given the percent compositions or masses. 20.2% Sodium, 37.6%Sulfur, 42.2% Oxygen, Molar mass: 682.8g/mol
20.2/23=0.8837.6/32=1.17542.2/16=2.63750.88/1.175/2.6375=3/4/9M(Na3S4O9)=23*3+32*4+16*9=341g/mol2*341=682Na6S8O18
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The empirical formula of a compound is CH. At 200 degrees Celsius, 0.242 of this compound occupies 97.2 mL at a pressure of 0.740 atm. What is the molecular formula of the compound
M=mRT/PV=0.242*8.314*(200+273.15)/(0.74*101.325*0.0972)=130(number of CH)=M/M(CH)=130/(12+1)=10Answer: C10H10.
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How many molecules of hydrogen gas are there in 8.32 g of Hepatanoic acid? Molar Mass of the Acid = 130.182 g/mol Molar Mass of Hydrogen = 1.008 g/mol
Solution:Heptanoic acid = C7H14O2Hydrogen gas = H2C7H14O2 → 7H2According to the scheme above: n(C7H14O2) = n(H2)/7Thus:(8.32 g C7H14O2) × (1 mol C7H14O2 / 130.182 g C7H14O2) × (7 mol H2...
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If the heat of combustion for a specific compound is -1500.0 kJ/mol and its molar mass is 75.47 g/mol, how many grams of this compound must you burn to release 769.90 kJ of heat?
1 mole : 1500 kJ = x mol : 769.90 kJ mol = 0.513 mass = 0.513 mol x 75.47 g/mol=38.7g
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A compound containing only carbon and hydrogen is found to contain 4.1315 g of carbon and 0.8685 g of hydrogen. Determine the empirical formula of hydrocarbon
CxHy w(C) = 4.1315 g / (4.1315 g + 0.8685 g) = 0.8263 w(H) = 0.8685 g / (4.1315 g + 0.8685 g) = 0.1737 x : y = 0.8263/12,0107...
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Naphthalene, (mothballs) consists of 93.7% carbon and 6.3% hydrogen by mass. Naphthalene has a molar mass of 128g mol L-1. Determine its molecular formula.
128 x 0.063 = 8.064.128 x 0.937 = 119.936 119.936/12 = 10.C10H8
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