A 1500.OmL container holds 7.80g of a gas at 2.35 atm and 25.00 C. How many moles of the gas are in the container ?

Pressure inside the container=34.91atm

Using the gas law: pV = nRT, and keeping the same number of moles of gas (n),we find the final volume V2:V2 = (T2/p2)*(p1*V1/T1) = (293 K/ 4.0 atm)*(2.0 atm...

BaCl2 + Na2SO4 -> BaSO4 + 2NaCln = m/Mn(BaCl2) = 80/208.23 = 0.384 molAs mole ratio n(BaCl2)=n(BaSO4), then n(BaSO4) = 0.384 molm(theoretical)(BaSO4) = M*n = 233.39*0.384 = 89.6 gm(actual)(BaSO4) =...

Density = mass\ volume Mass = volume × density = 25 cm3 × 80gcm-3 = 2000 g ( ans)

The total pressure of the mixture of gases equals the sum of the partial pressures of all gas present in the container:Ptotal = Poxygen + Phydrogen + Pnitrogen = 5...

Answer on Question #83513Container A holds 782 mL of ideal gas at 2.80 atm. Container B holds 174 mL of ideal gas at 4.40 atm. If the gases are allowed...

The de Broglie wavelength is the wavelength, λ, associated with a massive particle and is related to its momentum, p, through the Planck constant, h (6.62607015×10−34 J⋅s or kg⋅m2/s):{\displaystyle \lambda ={\frac {h}{p}}={\frac {h}{mv}}.}λ,= h/mv 80 g = 0,08 kg3 km/h...

Wavelength= h / mv = 6.63 x 10 -34 / 80 x 0.278 = 2.98 x 10 - 35

pV=nRTT = 295 KV = 0.5 L = 0.5*10-3 m3p = 1.442 bar = 144200 Pa R = 8.314 J/mol*Kn = pV/RT = (144200*0.5*10-3)/(8.314*295) = 0,029 mol.

4NH3 + 7O2 = 4NO2 + 6H2OAccording to the equation NH3 reacts completely, O2 is in the excess.7 mol of NO2 will be produced.According to the equation 7mol*7/4 = 12....