Litres of O2=72.7L O2
1 Answers 1 views5×1000= 50005000/100=50
1 Answers 1 viewsW=P*change in vol chnge in vol = 9 - 3 = 6 litres = 0.006m3 W=0.006*0.01*101325=6.0795 joule Answer: 6.0795 joule
1 Answers 1 viewsVolume in milliliters (ml)=760ml
1 Answers 1 viewsA = P x deltaV A = 1.013 x 10^3 x (5.6 - 3) x 2 mol А = 5.6728 x 10^3 J
1 Answers 1 viewsThe system is isobaric, so we can use the following equation for the work in system: A = pDelta;V p = 0.0100 atm - 1013.25 Pa; Delta;V = 0.0069 -...
1 Answers 1 views〖CH〗_4+〖2O〗_2→〖CO〗_2+〖2H〗_2 O ν=V/V_m ⇒ν~V V(O_2 )=2V(〖CH〗_4 )=30∙2=60 l. Air contains 21% O_2 by volume. V(air)=V(O_2 )/0.21=285.7≈286 l. Answer 286 l.
1 Answers 1 viewsAccording to the combined ideal gas equation:p1V1 = p2V2where p1 - initial pressure, V1 - initial volume, p2 - final pressure, V2 - final volume.From here:p2 = p1V1 / V2...
1 Answers 1 viewswe take the volume of the initial solution as x. the melting mass is 0.45 x. 20 liters of water is added to the solution. the volume of the solution...
1 Answers 1 viewsBoyle's Law can be expressed as P1V1 = P2V2initial pressure P1 = 125 Kpainitial volume V1 = 3.50 Lfinal pressure P2= ??final volume V2 = 1.75 LHence P2 = P1V1/V2P2 = 125 KPa...
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