Ca5(PO4)3F + 5H2SO4 = 3H3PO4 + 5CaSO4 + HF if 24.5 g Ca(PO4)3F is mixed with 89.7 g H2SO4, how much H3PO4 will form? NEED IT TODAY

You are right, the phosphate group comes from inorganic phosphate. During glucose metabolism, glucose -6- phosphate is formed due to phosphate donated by ATP. Glucose-6-phosphate can be converted into ribulose-5-phosphate...

𝛂H3PO4= 1×10ph= 1×106

H3PO4 is a trprotic acid,but the reactivity of cleavage ща proton determine the dissociation constant. For the third proton is much smaller than for the second and first H3PO4(s) +...

2H3PO4 + 3Ba(OH)2 --gt; Ba3(PO4)2 + 6H2O

The acidity constants of H3PO4 are the following:1) H3PO4 = H+ + H2PO4- Ka1 = 7.25*10-32) H2PO4- = H+ + HPO42- Ka2 = 6.31*10-83) HPO42- = H+ + PO43- Ka3...

Chemical reaction:3KOH + H3PO4 ⟶ K3PO4 + 3H2OMr (H3PO4)= 3(Ar(H)) + Ar(P) + 4(Ar(O))= 3 × 1+ 31 + 4 × 16 = 98 g/molMr = M = 98 molm(H3PO4)...

119.79 g of Ca3(PO4)2 is 119.79 g/310 g/mol = 0.386 mol and 66.07 g of H2SO4 is 66.07 g/98 g/mol = 0.674 mol of it. According to the equation 1...

H3PO4 + 3KOH --> K3PO4 + 3H2On (KOH) = (47.5mL x 0.10mol) / 1000 mL = 0.00475 moles of KOH present in 47.5 mL of the solution.According to the equation,...

2H3PO4+3Ca(OH)2=Ca3(PO4)2+6H2O1.we first find the amount of Ca(OH)2. To do this, we multiply the volume of Ca(OH)2 by the concentration (liter): 0.0155litr*0.1mol/litr=0.00155mol2.According to the above reaction, we find the amount of H3PO4:...

Given,Volume of H2SO4, (V1) = 25mlStrength of NaOH = 0.0965 m For the titration purpose Normal strength of NaOH will usedSo,Normally of the NaOH = (0.0965×no. of OH– in 1...