Answered Apr 23, 2024
250 ml × 0.4 = 100ml
= 100/2 = 50ml
Molar mass of sodium hydrogen carbonate = 84.007
Molarity = 111/84.007 = 1.32 mol
1.32/20
= 0.066mol/L
Concentration = Mass of the solute/Mass of the solution= 45/145 = 0.310.31*60 = 18.6g/mol
percent v/v is (mL ethanol/mL solution)×100.So you have 25.0 mL ethanol/250 mL(25/250)×100 = 10% v/v.
Half life of bismuth-214 is 20 min. 60 min / 20 min = 3 half life periods (1/2)^3 = 0.125 214 g x 0.125 = 26.75 g remains after 60...
100-0.92= 99.0899.08/100×100= 99.08%
Molecular weight of isotonic saline = 58.50.92×58.5 = 53.8253.92/100×100= 53.92%
Concentration of NaCl = amountof NaCl / L n of NaCl = 5.3 g/ 58.5 = 0.906 mol (but it is in 115 mL) In one L concentration is 1000/115...
The solution is 74.7% pure.
1 g = 1000 mg, 1 mg = 0.001 g1 L = 10 dL, 1 dL = 0.1 LFrom here:60 mg/dL = 60 × 0.001 g / 0.1 L =...
w=(m(salt))/m(solution) =(m(salt))/(m(water)+m(salt))×100%=(5.0 g)/(550 g+5.0g)×100%=0.90% Answer: 0.90%.
MOLAR MASS OF CUSO4.5H2O = 249.5 gm /mol ..given mass of CUSO4.5H2O = 0.10 g .So , moles of CUSO4.5H2O =( 0.10 / 249.5 ) mole .volume of water =...
Install the Bissoy app to consult with a doctor.
Log in to ask questions, provide answers, or leave comments.