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Throwing some scrap iron in a gold nitrate solution causes the gold metal to precipitate. How many liters of 0.5 M gold nitrate solution would react with 2.8x10<sup>23</sup> particles of iron metal?
Reaction:Au3+ + Fe = Fe3+ + AuV(Au(NO3)3 solution) = 2.8x1023/(6.02x1023)/0.5 = 0.93 LAnswer: 0.93 L
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Throwing some scrap iron in a gold nitrate solution causes the gold metal to precipitate. How many liters of 0.9 M gold nitrate solution would react with 8.3x10<sup>23</sup> particles of iron metal?
Gold nitrate solution volume =0.93L
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A metal has a specific heat capacity of .899 Jg-1K-1 How much energy is required to raise
the temperature of 2.00 kg of the metal by 80 K?
Energy is required=840kJ
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The specific heat capacity of copper metal is 0.385 J/g · K. How much energy is required to heat 204 g of copper from –17.7 °C to 28.5 °C?
Temperature change of 1 K = 1 0C. Thus, the energy required is:Q = 0.385 J/(g*K) * 204 g * (28.5 + 17.7) K = 3628.5 J
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Define heat capacity; molar heat capacity and specific heat capacity of a substance and give relations between them.
Heat capacity or thermal capacity is a physical property of matter, defined as the amount of heat to be supplied to a given mass of a material to produce a...
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What is the mass of a gold bar that is 7.379 × 10–4 m3 in volume? the density of gold is 19.3 g/cm3?
p=m/v m=p*v m=737,9*19,3=14241g=14,241kg
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What amount of heat is required to convert 1.0 g of water at 67.0°C to 1.0 g of steam at 100.0°C? (heat capacity of water = 4.184 J/g • C; ∆Hvap = 40.7 kJ/mol)
Q= Q1 + Q2Q1 = cm(T2 - T1) =4.184 *1.0*(100-67)= 138.072 JQ2= ∆Hvap*nn = m/M = 1.0 / 18.02 = 0.055 molQ2= 40700J /mol * 0.055 mol = 2239 JQ...
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The specific heat of a certain type of metal is 0.128 J/(g⋅∘C). What is the final temperature if 305 J of heat is added to 66.5 g of this metal, initially at 20.0 ∘C?
E = m*Cp*(T2 – T1)305 = 66.5 x 0.128 x (T2 – 20)305 + 170.24 = 66.5 x 0.128 x T2T2 = 475.24/8.512 = 55.83C55.83C
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It takes 150 J of energy to heat 10 g of substance 1 from 25oC to 50oC. It takes 250 J of energy to heat 10 g of substance 2 from 25oC to 50oC. Which substance has a higher specific heat capacity?
Substance 1: c=Q/(m*ΔT)=150/(10*25)=0.6 J/goCSubstance 2: c=Q/(m*ΔT)=250/(10*25)=1 J/goCAnswer: Substance 2 has a higher specific heat capacity
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There is a 9.2 g piece of gold. What volume will the gold have? (Density of gold = 19.4 g/cm^3) round answer to tenths place (1 decimal place)
V=m/pV=9,2/19,4=0,474=0,5Answer 0,5 см3
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