This reaction is the combustion of butane because the butane is reacted with oxygen to form carbon dioxide and water. To balance the equation, first balance the carbon atoms and...
1 Answers 1 viewsMolar mass of butane =58.1212/58.12=0.21molMolar mass of O2= 31.99812/31.998=0.38molMolar mass of CO2= 44.01Mole ratio CO2:O2= 8:13Mole ratio CO2: C4H10=8:2= 4.615Γ44.01Γ0.59=119.83gMolar mass of H2O=18.01528Mole ratio H2O:O2 =10:13Mole ratio H2O: C4H10=10:25.77Γ18.01528Γ0.59=61.33g
1 Answers 1 viewsZn:ZnCl2= 1:1=0.05molHCl: ZnCl2 =2:1= 0.075/2= 0.0375mole= 0.0875mole of ZnCl2
1 Answers 1 views2 v 2C2H6 + 7O2 --gt; 4CO2 + 6H2O 2*30 4*22.4 v = 2*4*22.4/60 = 2.986 L
1 Answers 1 viewsEquation of reaction: C4H10O + 6O2 rarr; 4CO2 + 5H2O 1 mol C4H10O produced 5 mol H2O, so to get 0.5599 mol water is necessary to take 0.5599/5 moles of...
1 Answers 1 viewsAnswer: C 4 H 10 O+6O 2 β 4CO 2 +5H 2 O All the coefficients are in place. The equation is in balance.
1 Answers 1 viewsCorrect
1 Answers 1 viewsFrom this reaction: C4H10O + 6 O2 = 4CO2 + 5H2O , a proportion can be made:x/6=36.7/4 ; Where x - moles of O2, needed to make 36,7 moles of CO2; 6...
1 Answers 1 viewsC4H10(g)Β + 6,5O2(g) β 4CO2(g) + 5H2O(l)n(C4H10)=m(C4H10)/M(C4H10)=56.20/58=0.969moln(O2)=m(O2)/M(O2)=85.30/32=2.666moln(C4H10)/1 and n(O2)/6.5 0.969/1 and 2.666/6.5 0.969 and 0.43The mass of water is calculated by the deficiency, by n(O2)n(O2)/n(H2O)=6.5/52.666*5=6.5*n(H2O)n(H2O)=2.05molV(H2O)=n(H2O)*Vm=2.05*22.4=45.92l=45920mlΟ(H2O)=1g/mlm(H2O)=Ο*V(H2O)=1*45920=45920gAnswer - 45920g
1 Answers 1 viewsn(O2):n(H2O)=1:2n(H2O)=5.12*2=10.24molAnswer: 10.24mol
1 Answers 1 views