pH = -lg [H + ]; 0.1m hcl: pH = 1; 0.5m hcl: pH = 0.3; 0.025m hcl: pH = 1.6; 0.0125m hcl: pH = 1.9.
1 Answers 1 viewsIn this case is important as behaving in a neutralization products in water HCl + NH3 = NH4Cl NH4Cl + H2O = NH4OH (weak base) + HCl (strong acid) so...
1 Answers 1 viewsV = 1L 0.05M X M HI = H+ + I- 1M 1M[H+]HI = X = 0.05M.Let Y moles of acetic acid be dissociated. Ymol Ymol YmolCH3COOH ⇄ CH3COO- + H+ 1mol 1mol 1molKa = [H+][CH3COO-]/[CH3COOH] = ([H+]HI + [H+]CH3COOH) ×[CH3COO-]/[CH3COOH] =...
1 Answers 1 viewsFe(s) + 2HCl(aq) → FeCl2(aq) + H2(g) – reaction occurs Cu(s) + 2HCl(g) → CuCl2(s) + H2(g) – reaction occurs at 600 Celcius Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)...
1 Answers 1 viewsIron and zinc force out hydrogen from hydrochloric acid: Fe + 2HCl → FeCl2 + H2↑ Zn + 2HCl → ZnCl2 + H2↑ Copper is among tension after hydrogen therefore...
1 Answers 1 viewsp =m/V 1,19 = 90/V V = 75,63 ml - it's volume of 37% HCL Need to solve a mass of full solution ( x = V(HCL)+(H2O) ), then 75,63...
1 Answers 1 views10M solution will be the most conductive, 1M will be 10 times worse to conduct electricity, 0.1M will be 100 times worse to conduct electric current. When dissolved in water,...
1 Answers 1 viewsAt first we will count the amount of HCl:n = c * V = 5 M * 4 L = 20 mol;Now we can find out the required mass of...
1 Answers 1 views1)C(HCl)=0.531/36.5=0.0145 mol/L2)n(HCl)=0.531*0.0115/36.5=1.673 *10^-4 mol3)pH=-lg[H+]=-lg(1.673*10^-4)=3.78
1 Answers 1 viewsa). CuO(s) + 2HCI(aq) → CuCl2(s) + H2O(aq)b). Na2CO3(s) + 2HCl(aq) → H2O(aq) + CO2(g) + 2NaCl(aq)c). 3NaOH(aq) + H3PO4(aq) → Na3PO4(aq) + 3H2O(aq)d). Ni(OH)2(aq) + 2CH3COOH(aq) → Ni(CH3COO)2(aq) +...
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