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In this case is important as behaving in a neutralization products in water HCl + NH3 = NH4Cl NH4Cl + H2O = NH4OH (weak base) + HCl (strong acid) so litmus paper will be red,because one of products of hydrolysis is stronger that another HCl (strong acid) CH3COOH + NH3 = CH3COONH4 CH3COONH4 + H2O = CH3COOH (weak acid) + NH4OH(weak base) HCl + NaOH = NaCl + H2O NaCl + H2O = NaOH (strong base) + HCl(strong acid) The color indicator will not change as the reaction product is not revealing any basic or acidic properties CH3COOH + NaOH = CH3COONa + H2O CH3COONa + H2O = CH3COOH (weak acid) + NaOH (strong base) so litmus paper will be blue,because one of products of hydrolysis is stronger that another NaOH (strong base).
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