25.0 g of an unknown metal at 90.0C is added to 50.0 g of water at 25.0 oC causing the temperature of the water rises to 29.8oC. What is the specific heat capacity and the identity of the metal?

Md Ariful Islam

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Md Ariful Islam

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qmetal = qwater By substitution, we have (metal values on the left, water values on the right): (mass) (Delta;T) (Cp) = (mass) (Delta;T) (Cp) (25.0)(90-29.8)(Cp) = (50.0)(29.8-25.0)(4.184 J g-1 deg;C-1) Cp = 0.667 J g-1 deg;C-1 There is no metal with such Cp in tables.
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