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If 23.32g CaCO3 and 65.3 mL 6.00 M HCl are mixed, how many grams of CO2 will be formed?
n of CaCO3=23.32/100=0.2332 mol n of HCl=0.3918 mol 6 mol --------1000 ml x mol---------65.3 ml x=0.3918 As can we see from reaction CaCO3 is in excess 0.3918 m CaCO3 +...
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when heated, KCl3 decomposes into KCl and O2. 2KCl3= 2KCl, how many grams of O2 were produced? if this reaction produced 49.2g KCl, how many grams of O2 were produced?
2KClO3=2KCl+3O2Per 1 gram of KCl there are 0.644 g O2 produced.Per 49.2 gram of KCl there are 31.678 g O2 produced.
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100g nitrogen mixed with 92g hydrogen
a) identity the limiting reagent
b) calculate the weight of amonia form
c) which reactent remains and how much
n of N2 = 100/14=3.57 moles n of H2= 92/2 =46 H2 is in access ,so N2 is limiting reagent,and H2 remains (46-3*3.57=35.29) 3.57 2*3.57 N2 + 3H2 = 2NH3...
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Observe the following RXN:
CH4 + O2 --> CO + 2H2O
Carbon has a mass of 12 amu, Hydrogen 1 amu and Oxygen 16 amu.
If 16g of CH4 and 32g of O2 are reacted, how much CO is produced?
The amount of CH4 is n(CH4) = m(CH4)/M(CH4) = 16/16 = 1 mol The amount of O2 is n(O2) = M(O2)/M(O2) = 32/32 = 1 mol According to the reaction...
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When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen are formed. How many grams of water are formed?
You can calculate this by such reaction: NH₄NO₃ --gt; N₂ + frac12;O₂ + 2H₂O ==gt; 2NH₄NO₃ --gt; 2N₂ + O₂ + 4H₂O The law of conservation of mass solves this...
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If you start with 25.0 grams of lead (II) nitrate and 15.0 grams of sodium iodide, how many grams of sodium nitrate can be formed?
Pb(NO3)2 + 2NaI = 2NaNO3 + PbI2n = m / MM (Pb(NO3)2) = 331.2 g/molM (NaI) = 150 g/molM (NaNO3) = 85 g/moln (Pb(NO3)2) = 25 / 331.2 = 0.08...
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A 0.4230 g sample of impure sodium nitrate was heated, converting all the sodium nitrate to .1235 g of sodium nitrate and oxygen gas. Determine the percent of sodium nitrate in the original sample.
Answer:2HNO3 = 2HNO2 + O2m= 85 x 0.1235 / 69= 0.1521W%= 0.1521 / 0.4230 = 36%
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what mass of copper II nitrate can be produced from a reaction of 3.72 grams of copper with 9.83 grams of silver nitrate, according to the following equation?
Cu+2AgNO3 → 2Ag + Cu(NO3)2n=m/M ; n - number of moles; m - mass of substance; M - molar mass of the substance;n(Cu)= 3.72/64 = 0.058 moles;M(AgNO3)= 108+14+48=170;n(AgNO3) =9.83/170= 0.058...
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How many moles of oxygen are produced when 756 grams of lead 11 oxide are formed
Find the mass of nitrogen dioxide that forms with 0.58 moles of oxygen
1) 2 Pb + O2 = 2 PbOthe amount of PbO is 756 g / 223.2 g/mole = 3.38 mole, it is twice of moles of O2, i.e.the amount of...
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When 23 grams of methane gas combine with 42 grams of oxygen, 37 grams of water form, plus carbon dioxide. What mass of carbon dioxide is produced?
CH4(g) + 2 O2 (g) = CO2(g) + 2 H2O (g)1 : 2 : 1 : 223g : 42g : ? : 37g Therefore : ( 23/42) =0.5 moles 1...
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