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A solution is made by dissolving 1.25 g of C2H5OH in 11.6 g of H2O. Calculate the mass percent of C2H5OH, the mass percent of H2O, molality of C2H5OH.
Mass of C2H5OH = 1.25 g Mass of H2O = 11.6 g Mass percent of C2H5 OH = 1.25 × 100 / 1.25 + 11.6 = 125 / 12.86...
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If 355 g of ethanol (C2H5OH), molar mass = 46 g / mol is added to 645 g of water,what is the molality of the ethanol? A 0.550 m B.7.71 m C.11.9 m D.21.7 m
A 0.550 m
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assume a bottle of wine consist of an 11% solution (by weight) of ethanol in water. if the bottle of wine is chilled to -20 degree celsius will the solution begin to freeze ?
11/100×-20=-2.2=-20+-2.2=-22.2°C
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A mixture of ethanol, C2H5OH, and water has a freezing point of −16.0 °C. (a) What is the molality of the alcohol? (b) What is the weight percent of alcohol in the solution?
Depression in freezing point is denoted by,Freezing point of water + Freezing point of solutionFrom the given dataButWhere freezing point depression constant for water
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A solution of ethanol is prepared by dissolving 25.0 ml of ethanol in enough water to give a total volume of 250.0 ml. What is the percent-by-volume concentration of ethanol?
percent v/v is (mL ethanol/mL solution)×100.So you have 25.0 mL ethanol/250 mL(25/250)×100 = 10% v/v.
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Ethanol burns according to the following equation. C2H5OH + 3O2 > 2CO2 +3H2O if 15.0 mole of C2H5OH burns this way, how many moles of oxygen are needed?
21,91 mole
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A sample of rubbing alcohol solution contains ethanol, C2H5OH(l). If the sample contains 1.25x10^23 atoms of hydrogen in the ethanol, what amount in moles of ethanol is in the sample?
The amount of moles for atom\molecule\compound etc. can be calculated based on amount of atom\molecule\structural units etc. using Avogadro constant (NA=6.02x10^23) that represents 1 mole. One molecule of ethanol consists...
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Explain how you would separate mixture of nitrogen and oxygen gases given that their boiling point are _196 degree Celsius and 183 degrees Celsius respectively
There are several ways of separating nitrogen and oxygen. The first involves cooling the mixture down to -200 degrees Celsius and separating the gases using a process called fractional distillation....
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A sample of a wine contain 28% C2H5OH by volume and rest is H2O. Calculate mole fraction of
C2H5OH in wine, density of C2H5OH = 0.79 gm/ml, density of water = 1 gm/ml.
0.28 x 0.79 = 0.22 g.0.22/46 = 0.004 .
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What is the boiling point of a 0.66 molal solution of sucrose (nonelectrolyte) in ethanol? (Kb of ethanol = 1.22 °C/m, normal boiling point of ethanol is 78.5 °C)
∆Tb=Kb*Cm=1.22*0.66=0.81 °C;Tb(solution)=78.5 - ∆Tb=77.69 °C;Answer: 77.69°C
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