For the reaction of cupric oxide with sulfuric acid, the balanced chemical equation is CuO plus H₂SO₄ react to form CuSO₄ plus H₂O.
1 Answers 1 viewsv=0.139/22=0.006molV=0.126/0.006=21ml
1 Answers 1 viewsMolecular weight of H2SO4 is 98.079 g-mol.1 ml equals 1.84 g. Hence, 96.4ml equals 96 x 1.84 = 177.376g.Therefore, 100 ml volume contains 177.376 g H2SO4. So 1 liter contains...
1 Answers 1 views2K + H2SO4 = K2SO4 + H2 if m(H2) = 6 g, so n(H2) = 6 g / 2 g/mol = 3 moles; n(H2) : n(K2SO4) = 1 : 1;...
1 Answers 1 views110 g/cc is larger than the density of iridium. Certainly you meant 1.10 g/cc. To ease the calculations, take 1 liter of the solution. Its mass is m = V*D...
1 Answers 1 viewsm(CH3CH2OH) = 2,5g n(CH3CH2OH) : n(CH3COOH) = 1: 1 m(CH3COOH) = ? X g 2.5g CH3CH2OH → CH3COOH 46 g/moll 60 g/moll 46g (CH3CH2OH) ─ 60g (CH3COOH) X g (CH3CH2OH)...
1 Answers 1 viewsReaction of neutralization of sulfuric acid by potassium hydroxide: H_2 SO_4+2KOH=K_2 SO_4+H_2 O Using the Law of equivalence: n(H_2 SO_4 )=n(KOH) c(H_2 SO_4 )∙V(H_2 SO_4 )=c(KOH)∙V(KOH) c(KOH)=(c(H_2 SO_4 )∙V(H_2 SO_4...
1 Answers 1 viewsIf we have 1L of solution, then we have 100 ml (0.1L = 10% from 1L) of sulphuric acid in it. Find the mass of 100 ml of sulphuric acid:...
1 Answers 1 viewsxmol 0.0054molBa(OH)2 + 2HBr = BaBr2 +2H2O 1mol 2mol n(HBr) = C(HBr) × V(HBr) = 0.225M × 0.024L = 0.0054mol.n(Ba(OH)2) = x = 0.0054 × 1 / 2 mol = 0.0027mol.V(Ba(OH)2) = n(Ba(OH)2) /...
1 Answers 1 viewsSolution: C(KOH) = n(KOH)/V(solution)n(KOH) = C(KOH)*V(KOH) = 0.5 M* 1L = = 0.5 molm(KOH)= n(KOH)*M(KOH) = 0.5 mol*56 g/mol = 28 g
1 Answers 1 views