A. HNO3
1 Answers 1 viewsMolar mass of Zinc nitrate = 189.36 189.36 × 0.018 =3.41×10 = 34.1= 500× 0.15/34.1= 2.2cm3
1 Answers 1 viewsActual Yield =216.43g
1 Answers 1 views1. 4Zn(s) + NO3-(aq) + 6H+(aq) -> 4Zn2+(aq) + NH3 + 3OH-(aq)2.3Cu(s) + 2NO3-(aq) + 8H+ (aq)-> 3Cu2+(aq)+2NO + 3S + 4H2O
1 Answers 1 viewsSolution:Each mol of Ca(NO3)2 (MM 164.088) contains 2 mol NO3- (MM 62.005),so the fraction of mass that is nitrate (NO3-) is:(2 mol NO3- / 1 mol Ca(NO3)2) × (62.005 g...
1 Answers 1 viewsSolution:(a) Ca(s) + Cu(NO3)2(aq) → Cu(s) + Ca(NO3)2(aq)_______________________________________________Ca(s) − 2e- → Ca2+(aq) (oxidation half-reaction)Cu2+(aq) + 2e- → Cu(s) (reduction half-reaction)----------------------------------------------------------------------------Ca(s) + Cu2+(aq) → Ca2+(aq) + Cu(s)(b) Zn(s) + Ni2+ → Ni(s) +...
1 Answers 1 viewsSolution:0.144 mM Ca(NO3)2 = 0.144 mmol Ca(NO3)2 / LThe molar mass of Ca(NO3)2 is 164.088 g/molBecause 1 mol of Ca(NO3)2 is 164.088 g, by extension, 1 mmol = 164.088 mg1...
1 Answers 1 views1. AgNO3(aq) +KCl(aq) ----> KNO3(aq) + AgCl (s) Ag+ + NO3- +K+ + Cl- ----> K+ + NO3- + AgCl(s) Ag+ + Cl- ----> AgCl(s) 2. CuCl2(aq) + Ba(NO3)2(aq) ----->...
1 Answers 1 viewsIt is necessary to take 2 tanks, connect them with salt bridges from KCl. In the first you need to pour a solution of lead nitrate and lower the lead...
1 Answers 1 viewsAnswer: 1) Balance the reaction equation Ba(NO3)2 + Na2SO4 ---> BaSO4 + 2 NaNO3 2) Calculate number of moles of Ba(NO3)2 = 0.50 moles/L x 0.025 L = 0.0125 moles 3) Using stoichiometry...
1 Answers 1 views