(a) How many ppm of Ca(NO3)2 are in 0.144mMCa(NO3)2?

Md Ariful Islam

0 like 0 dislike
1 views
Share with your friends

1 Answers

Md Ariful Islam

Call

Solution:

0.144 mM Ca(NO3)2 = 0.144 mmol Ca(NO3)2 / L

The molar mass of Ca(NO3)2 is 164.088 g/mol

Because 1 mol of Ca(NO3)2 is 164.088 g, by extension, 1 mmol = 164.088 mg

1 mmol = 164.088 mg

Therefore, 0.144 mmol is:

(0.144 mmol) × (164.088 mg / 1 mmol) = 23.63 mg Ca(NO3)2 = 23.6 mg Ca(NO3)2

ppm = 1 mg/L

Therefore, 23.6 mg/L = 23.6 ppm

Answer: 23.6 ppm of Ca(NO3)2

0 like 0 dislike
1 views
Talk Doctor Online in Bissoy App
If 1,000.0 g of water from Luboc River contains 0.0075g of Ca<sup>2+</sup> ions, how many parts per million (ppm) of calcium ions

PPM is a term used in chemistry to denote a very, very low concentration of a solution. One gram in 1000 ml is 1000 ppm and one thousandth of...

1 Answers 1 views
the stock solution for this experiment contains 0.7218g of KNO3 in 1000cm3 of water. the manual claims that this solution represents a 100 ppm solution of NO3-N. how do i prove that this is the case.

100ppm means 100 parts per million. W of NO3^- = (N of NO3^-) / ( N of H2O) , N is number of particles. 0.7218g N of NO3^- KNO3 -------gt;...

1 Answers 1 views
how many grams of NaCl should be weighed to prepare 1.00L of 601 ppm solution of Na+? how many grams of NaCl should be weighed to prepare 1.00 L of XYZ ppm solution of Na+?

Quantity of NaCl =4.72g

1 Answers 1 views
A solution contains 12.6 ppm of dissolved Ca(NO3)2. Calculate the concentration of NO3  in moles per litre. (4)

Solution:Each mol of Ca(NO3)2 (MM 164.088) contains 2 mol NO3- (MM 62.005),so the fraction of mass that is nitrate (NO3-) is:(2 mol NO3- / 1 mol Ca(NO3)2) × (62.005 g...

1 Answers 1 views
How many grams of solid BaSO4 will form when Na2SO4 reacts with 25mL of 0.50 M Ba(NO3)2? _Ba(NO3)2 + _Na2SO4 ---&gt; _ BaSO4 + _ NaNO3 Show all calculations

Answer: 1) Balance the reaction equation Ba(NO3)2 + Na2SO4 ---&gt; BaSO4 + 2 NaNO3 2) Calculate number of moles of Ba(NO3)2 = 0.50 moles/L x 0.025 L = 0.0125 moles 3) Using stoichiometry...

1 Answers 1 views
Use the following equation: Pb(SO4)2 + 4 LINO3 → Pb(NO3)2 + 2LI2SO4 How many moles of LINO3 are needed to make 6.34 mol of Pb(NO3)4?

25.36 moles

1 Answers 1 views
When 25.00 mL of 3.42 M Pb(NO3)2 reacts with excess NaCl, how many grams of PbCl2 form? Pb(NO3)2(aq) + 2 NaCl(aq) → PbCl2(s) + 2 NaNO3(aq)

Mole = concentration × volume Mole = 3.42M ×( 25 × 10-3 L)Mole = 0.0855 mole1 mole of Pb(NO3)2 = 278.1 g PbCl20.0855 mole = 278.1 × 0.0855 g PbCl2...

1 Answers 1 views
How many milliliters of 1.90 M Pb(NO3)2 Pb(NO3)2 will react with 40.0 mL of 1.40 M KCl?

Pb(NO3)2 + 2KCl=PbCl2+ 2 KNO3n(KCl) = c*V=1,4*40*10-3= 0,056 molen(Pb(NO3)2)= 0,056/2=0,028 moleV(Pb(NO3)2)=n/c=(0,028/1,90)*103=14,74 mLAnswer: 14,74 mL Pb(NO3)2

1 Answers 1 views
Question 1: Express 4874 ppm as a %W/W concentration. Question 2: Convert 0.548 ppm to ppb.

4874 ppm as a %W/W concentration:1 ppm = 1 mg / L For diluted solution 1 ppm = 1 mg / kg = 1 mg / 1000 g4874 ppm =...

1 Answers 1 views
Given the following reaction: CaCl2 (aq) + 2AgNO3(aq) Ca(NO3)2(aq) + 2agCI(s) How many moles of Ca (NO3)2 be produced by 9 moles of CaCI2?

CaCl2 (aq) + 2AgNO3(aq) = Ca(NO3)2(aq) + 2АgCI(s)Based on the chemical reaction equation, the ratio of CaCl2 to Ca(NO3)2 will be 1: 1 (1 mole of calcium chloride will give...

1 Answers 1 views
X