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30 grams of potassium chlorate are dissolved in 100 grams of water at 90 degrees C grams of potassium chlorate will precipitate when this solution is cooled to 25 degrees c
C = 100-30= 70 grams
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When potassium chloride reacts with oxygen under the right conditions, potassium chlorate is formed: 2 KCI+ 3O2-->KCIO3
2 KCI+ 3 O2 --> 2 KCIO3
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Calculate the mass in g of potassium chloride and volume in dm3 of oxygen gas produced at S.T.P when 100g potassium chlorate is decomposed
2KClO3….>2KCl+3O2No of Moles of KClO3=mass/RMM=4.72/122.5=0.0385 MolesNo of Moles of oxygen=3×0.0385/2=0.058Mass of oxygen=no.of Moles×RAM=0.058×32=1.85g100g =70 litres1.85g=?70×1.85/1000=0.195 litres
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suppose we are preparing a solution of potassium permanganate KMno⁴ and need about 0.10 mol of the compound (that is 0.10 mol KMno⁴) How many grams of the compound do we need
Let the weight required be x g.Molarity c=0.1 MNumber of moles of KMnO4 is n=158.034 x moles The volume of solution in litrs is V=1000 250=0.25 litresMolarity of the given solution is given as c=V nc=0.25 158.034 x=0.1⟹x=158.034×0.1×0.25⟹x=3.95 gTherefore, weight of KMnO4 required is 3.95 g.
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Q- 3 g C^2H^4 gas requires oxygen gas ( O^2) for combustion which is obtained from pure Potassium Chlorate ( KClO^3). Mass of Potassium Chlorate is ____ ?
C2H4 + 3O2 = 2CO2+2H2O From the equation, 1 mole of C2H4 requires 3 moles of O2 for combustion. Consequently 3 g of C2H4requires X grams of O2 X =...
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<ol><li>10 mol of Zn react with 10 mol of HCl. Calculate the number of moles of H2 produced.</li></ol> (a) 5 mol (b) 10 mol (c) 20 mol (d) 2.5 mo
ANSWER SHOUD BE "a".EXPLANATION ......Zn reacts with HCl and form ZnCl2 and H2 .Balance Reaction is Zn + 2HCl ----- ZnCl2 + H2 .When 10 mol of Zn react with...
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How many moles of aluminum chloride are produced when 92.30 g of aluminum chlorate is heated in a decomposition reaction?
The decomposition of aluminum chlorate can be shown as follows:Al(ClO3)3 = AlCl3 + O2From here:m (AlCl3) = m (Al(ClO3)3) × Mr(AlCl3) / Mr(Al(ClO3)3) = 92.30 g × 133.34 g/mol /...
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Oxygen gas and potassium chloride react to form potassium chlorate What’s the formula for this?
KClO3
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how many moles of oxygen are produced by the decomposition of 9.08 moles of potassium chlorate?
13.62
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If 7.0 moles of nh3 reacts with 14 moles of o2, how many moles of no2 will be produced?
Calculate how many moles of excess reactant will remain
4NH3 + 7O2 = 4NO2 + 6H2OAccording to the equation NH3 reacts completely, O2 is in the excess.7 mol of NO2 will be produced.According to the equation 7mol*7/4 = 12....
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