Answered Apr 21, 2024
Freezing point of water = 0°C
Boiling point of water = 100°C
Cwater = 4.2 Jg-1°C-1
q = m × c × ∆T
m = q/∆T × c
= 42.6/(100-0) × 4.2
= 0.01g
d,e
pH= -log[H+]pH= -log[1×10^-3]pH= 32) pH= -log[3.6×10^-5]pH= 5-log3.6pH= 4.44
H= mcΔtm= H/cΔt= 42000/(4.2×100) = 100g
a) 4x3
D) 2.408 x 1024 molecules of water
147N+42He→178O+11H714N+24He→817O+11H is an example of a fission reaction
Energy (n), angular momentum (ℓ), magnetic moment (mℓ), and spin (ms).
1 cubic metre =1000 litres10l = 1×10/1000 = 0.01B. 0.01m3
Solution:q = m × C × ΔTq = m × C × (Tf - Ti),where:q = amount of heat energy gained or lost by substancem = mass of sampleC = specific heat...
Average atomic mass of element A: (56 x 60 + 58 x 30 + 59 x 10) / 100 = 56.9
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