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What volume of 0.300 M calcium chloride contains 3.50g of calcium chloride
3.50g CaCl2 × (1mol CaCl2 /110.98g CaCl2)= 0.0315 molesMolarity = no. of moles / volume 0.300 = 0.0315 / volume Volume = 0.0315/0.300Volume = 0.105 L
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The compound calcium chloride is a strong electrolyte. Write the reaction when solid calcium chloride is put into water:
Mixing calcium chloride with water is an exothermic reaction, which means that the combination of the two substances releases heat. Thus, when you add calcium chloride to water, the solution...
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When 15.25 grams of A reacts with 34.22 grams of B, 18.69 grams of C is produced. How many grams of D are produced?
30.78 g
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. How many grams of calcium chloride are needed to prepare 72 g of silver chloride according to the following equation? СаСl2 + AgNO3 → Са(NО3)2 + AgСl
=27.876g of Calcium Chloride
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Calculate which one of the following contains more grams of calcium; 4.6 ×10²⁰ atoms of calcium or 0.050mol of calcium.
4.6×1020/6.022×10230.000764molHence 0.050mol contains more grams
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When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen are formed. How many grams of water are formed?
You can calculate this by such reaction: NH₄NO₃ --gt; N₂ + frac12;O₂ + 2H₂O ==gt; 2NH₄NO₃ --gt; 2N₂ + O₂ + 4H₂O The law of conservation of mass solves this...
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Calculate the moles of calcium chloride (CaCl2) needed to react in order to produce 85.00 grams of calcium carbonate (CaCO3).
The reaction between the mentioned substances can be shown as following:CaCl2 + Na2CO3 = 2NaCl + CaCO3First, the mass of CaCO3 should be converted into moles:n = m/Mrwhere n -...
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Using the following chemical equation how many grams of calcium chloride can be produced by reacting 57.09 g of calcium hydroxide? 2HCl + Ca(OH)<sub>2</sub> -> 2H<sub>2</sub>O + CaCl<sub>2</sub>
2HCl + Ca(OH)2 -> 2H2O + CaCl2According to the equation, the mass of calcium chloride equals:m(CaCl2) = m(Ca(OH)2) × Mr(CaCl2) / Mr(Ca(OH)2) = 57.09 g × 110.98 g/mol / 74.09 g/mol...
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which one of the fol compounds does not cause hardness of water.
1.magnesium chloride
2. calcium chloride.
3.magnesium sulphate.
4. sodium chloride
4. sodium chloride
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According to the following reaction, how many grams of ammonium chloride are needed to form 30.8 grams of hydrochloric acid?
ammonium chloride (aq) ammonia (g) + hydrochloric acid (aq)
. m (HCl) =30.8 g .m (NH4Cl)=? The reaction is NH4Cl= NH3 + HCl Let's find the amount of substance (HCl)= m(HCl)/ Mr(HCl) Mr (HCl)= Ar(H)+ Ar(Cl)=1+35.5= 36.5 . n=30.8/36.5=0.84...
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