The density of a solid gold at room temperature is 19.3 g/mL, Given a 45-mg sample of gold, what is the volume in mL?

Reaction:Au3+ + Fe = Fe3+ + AuV(Au(NO3)3 solution) = 2.8x1023/(6.02x1023)/0.5 = 0.93 LAnswer: 0.93 L

Gold nitrate solution volume =0.93L

There are weak attractions between molecules of Cl2 meaning little energy is needed to break these forces of attraction and therefore Cl2 has a low boiling point. NaCl on the other hand has strong electrostatic forces...

The molar mass of O2 is 32.00 g/molThe molar mass of Au is 196.97 g/molSolution:Balanced chemical equation:Au + O2 ⟶ AuO2According to stoichiometry:(15.76 g Au) × (1 mol Au /...

Because chocolates and chocolate fondue are consisted from different mixtures of chocolate and other components, so mixtures of different composition, appear different properties, one of which is the melting temperature.

A bulk sample is the physical sample of a large volume or tonnage of mineral material taken from a known resource area for investigative purposes.Primary sampling unit refers to Sampling...

The density of a piece of gold is its mass per unit volume. d(Au) = m(Au) / V(Au) The volume of the piece of gold is: V(Au) = 3118.97 g...

Density of gold = 19.3 g/mLMass of gold = 4.0 gSolution:Equation:Density = Mass / VolumeRearrange the equation to isolate volume and solve.Volume = Mass / DensityVolume = (4.0 g) /...

Solution:gold = AuDensity of a substance is given byDensity = Mass / VolumeMass = Density × VolumeTherefore,(19.3 g Au / 1 mL) × (5 mL) = 96.5 g AuAnswer: 96.5 grams...

p=m/v m=p*v m=737,9*19,3=14241g=14,241kg