How do I find the area of a rectangle if width and perimeter are given?

Use the Pythagorean theorem to find the sides and then find the perimeter.

For the perimeter, add the four sides together and simplify. For the area, multiply the length by the width.

Divide the area by the length, giving you the width. Add twice the width to twice the length.

Let x = the width. Then the length is 2x - 7. The perimeter is twice the width plus twice the length: 64 = (2x) + 2(2x - 7) =...

Such a rectangle would have its sides and diagonal in the ratio of 2:1:√5 (per the Pythagorean theorem). The ratio of √5 to the diagonal (20) is equal to the...

The perimeter of a regular pentagon is the apothem multiplied by 7.267.

Use the Pythagorean Theorem to find the other side. Then multiply the length by the width.

Use the Pythagorean Theorem (a^2 + b^2 = c^2). A and B are the lengths of the two sides of the rectangle. To get the length of the hypotenuse, you...

You can't. With any given perimeter, an infinite number of length-width combinations would be possible.

Let B equal the breadth. Then 2B equals the length. Write an equation in B, stating that the perimeter is equal to twice the breadth plus twice the length. Solve...