The perimeter of a rectangle is 64 feet. Length is 7 feet less than 2 times the width. What are the dimensions of the rectangle?

For the perimeter, add the four sides together and simplify. For the area, multiply the length by the width.

Multiply 104 x 208 x 14 to find the answer.

Divide the area by the length, giving you the width. Add twice the width to twice the length.

The perimeter equals the side length times the number of sides. In this case, multiply 21 by 9 and you will get a perimeter of 189.

Such a rectangle would have its sides and diagonal in the ratio of 2:1:√5 (per the Pythagorean theorem). The ratio of √5 to the diagonal (20) is equal to the...

Use the Pythagorean Theorem to find the other side. Then multiply the length by the width.

Use the Pythagorean Theorem (a^2 + b^2 = c^2). A and B are the lengths of the two sides of the rectangle. To get the length of the hypotenuse, you...

You can't. With any given perimeter, an infinite number of length-width combinations would be possible.

Let B equal the breadth. Then 2B equals the length. Write an equation in B, stating that the perimeter is equal to twice the breadth plus twice the length. Solve...

Double the width, and subtract that from the perimeter. Then divide that number by two, which gives you the length of the rectangle. Then, multiply the result by the width...