The heat of fusion for water is 80. cal/g. How many calories of heat are needed to melt a 35 g ice cube that has a temperature of 0 C?

Md Ariful Islam

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Md Ariful Islam

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The formula for the heat required to melt a solid is

$color(blue)(|bar(ul(color(white)(a/a) q= mΔ_"fus"H^°color(white)(a/a)|)))" "$

where

$q = "the amount of heat"$
$m = "the mass of the solid"$
$Δ_"fus"H^° = "the enthalpy of fusion"$

$m = "35 g"$
$Δ_"fus"H^° = "80. cal·g"^"-1""$

∴ $q = 35 color(red)(cancel(color(black)("g"))) × "80. cal"·color(red)(cancel(color(black)("g"^"-1"))) = 2bar8 00color(white)(l) "cal" = 2.8 × 10^3 color(white)(l)"cal"$

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