How much heat is required to convert 20.0 g of ice at -50.0°C to liquid water at 0.0°C? The specific heat of ice is 2.06 J/(g *$"^o$C) and the heat of fusion of water is 334 J/g?

Md Ariful Islam

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Md Ariful Islam

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We interrogate the process.....

$H_2O(s)stackrel(Delta_1, -20^@C...0^@C)rarrH_2O(s)stackrel(Delta_2=Delta_"fusion")rarrH_2O(l)$

Now $Delta_1=20.0*gxx2.06*J*g^-1*""^@C^-1xxDeltaT=$

$20.0*gxx2.06*J*g^-1*""^@C^-1xx50$ $""^@C=2060*J$

And $Delta_2=20.0*gxx334*J*g^-1=$

$20.0*gxx334*J*g^-1=6680*J$

$"Total heat"=Delta_1+Delta_2=2060*J+6680*J=??*J$

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