When you look at the big picture, what you have is heat flowing out of solid iron and cooling it down. So, you have to use the heat flow equation:...
1 Answers 1 viewsThe equation to use is $Q=mcDeltaT$, where $Q$ is the energy in Joules, $m$ is the mass, $c$ is the specific heat, and $DeltaT$ is the change in temperature. $DeltaT=T_"final"-T_"initial"$...
1 Answers 1 viewsThe of aluminium tells you the amount of energy needed to increase the temperature of $"1 g"$ of aluminium by $1^@"C"$. $c_ "Al" = "0.214 cal g"^(-1)""^@"C"^(-1)$...
1 Answers 1 viewsThe trick here is to realize that because the sample of metal has the same mass in both cases, you can say that $q_2 = (DeltaT_2)/(DeltaT_1) * q_1$...
1 Answers 1 viewsThe key to this problem is the of iron, which is said to be equal to $c_"iron" = "0.449 J g"^(-1)""^@"C"^(-1)$ As you know, the specific heat...
1 Answers 1 views$H_2O(s) +DeltararrH_2O(l)$....... Note that BOTH the ice and water have a specified temperature of $0$ $""^@C$, and thus we assess the heat involved in the phase change, and thus we...
1 Answers 1 viewsAnd so we simply take the product... $"mass"xx"C"_"specific heat"xxDeltaT=100.0*gxxunderbrace(0.492*cal*g^-1*""^@C^-1)_"quoted specific heat"xx19.5*""^@C=+959.4*cal$....the positive sign indicates heat is ADDED to the system.
1 Answers 1 viewsUnsurprisingly, the key to this problem is the hint. The thing to remember about a substance's is that it tells you the amount of energy needed in order...
1 Answers 1 viewsHere, we're relating a few things: (1) the mass of the substance, (2) its , and (3) its temperature change with the equation, $q = mC_sDeltaT$ Before we start, that...
1 Answers 1 viewsThe key to this problem lies in the value of the of iron. $c_"iron" = "0.108 cal"$ $color(blue)("g"^(-1))color(darkorange)(""^@"C"^(-1))$ This tells you that in order to increase...
1 Answers 1 views