There is no coefficient in front of the $N_2$ in the reactants. This means that there is one mole of $N_2$ required in the balanced equation. There is a...
1 Answers 1 viewsOne thing I think it's interesting to note is that you'll never be able to have that reaction happen in the standard temperature and pressure; you can, however, have the...
1 Answers 1 viewsNotice the coefficients of $N_2$ and $H_2$. Since the equation has an $N_2$ and $3H_2$, $3$ times as many moles of $H_2$ will be used as $N_2$ assuming a complete...
1 Answers 1 viewsIn this scenario, $"Le Chatelier's principle"$ would predict that the equilibrium would be driven to the side of the reaction that exerts least pressure, i.e. the product side. Note that...
1 Answers 1 viewsBefore doing any calculation, take a look at the values of the equilibrium concentrations for the three chemical species that take part in the reaction. Notice that the concentrations of...
1 Answers 1 viewsAs you know, the equilibrium constant for a given chemical equilibrium depends on the equilibrium concentrations of the chemical species that take part in the reaction the stoichiometric...
1 Answers 1 viewsUse the definition of $K_(eq)$. $K_(eq) = (["products"]^(d,e,f, . . . ))/(["reactants"]^(a,b,c,. . . ))$ $= (["NH"_3]_(eq)^2)/(["H"_2]_(eq)^3["N"_2]_(eq))$ Just make sure you remember to use stoichiometric coefficients correctly. $3H_2$...
1 Answers 1 views$"Le Chatelier's principle states that when a system at....."$ $"equilibrium is subject to an external stress, the equilibrium"$ $"will move so as to oppose the external stress"$. As I...
1 Answers 1 viewsThe problem provides you with the thermochemical equation that describes the synthesis of ammonia from nitrogen gas and hydrogen gas. $"N"_ (2(g)) + 3"H"_ (2(g)) -> 2"NH"_ (3(g))" "DeltaH_...
1 Answers 1 viewsFirst of all, write out the equations $Sn(s) + Cl_"2"(g) -> SnCl_"2"(s)$ $DeltaH = -325kJ$ $SnCl_"2"(s) + Cl_"2"(g) -> SnCl_"4"(l)$ $DeltaH = -186kJ$...
1 Answers 1 views