According to the following reaction how many moles of carbon dioxide will be formed upon the complete reaction of 28.2 grams of carbon (graphite) with excess oxygen gas?

Md Ariful Islam

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Md Ariful Islam

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$C(s) + O_2(g) rarr CO_2(g)$.

The $1:1$ is clear: moles of carbon, and dioxygen gas are equivalent to the moles of carbon dioxide gas generated.

We start with $(28.2*g)/(12.01*g*mol)=2.35*mol$ $C$, and thus $2.35*molxx44.01*g*mol^-1$ $CO_2(g)$ are evolved.

Suppose that less than $100*g$ of gas were collected in the experiment. Barring error on the part of the experimenter, what would be a reasonable explanation?

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