Silicon tetrachloride ($SiCl_4$) can be prepared by heating $Si$ in chlorine gas: $Si (s) + 2Cl_2(g) -> SiCl_4(l)$. In one reaction, 0.507 mole of $SiCl_4$ is produced. How many moles of molecular chlorine were used in the reaction?

Md Ariful Islam

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Md Ariful Islam

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The stoichiometric equation, which you have correctly written, clearly and explicitly shows that $1$ $mol$ of silicon (approx. $28*g$) reacts with $2*"moles"$ of chlorine gas (approx. $71*g$) to give $1$ $mol$ of $SiCl_4$.

The equation establishes both the molar and mass balance.

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