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The reaction is:

$2Na(s)+O_2(g)->Na_2O(s)$

So, ratio between sodium and sodium oxide is $2:1=2$.

Therefore, if ten moles of sodium are used, then we produce:

$10color(red)cancelcolor(black)("mol" \ Na)*(1 \ "mol" \ Na_2O)/(2color(red)cancelcolor(black)("mol" \ Na))=5 \ "mol" \ Na_2O$

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