What is the mass of $3.543 * 10^23$ atoms of magnesium?

Md Ariful Islam

0 like 0 dislike
1 views
Share with your friends

1 Answers

Md Ariful Islam

Call

Molar mass of $"Mg"$ is $"24.3 g/mol"$

It means $"1 mol"$ of $"Mg"$ atoms weigh $"24.3 g"$

Mass of $3.543 × 10^23\ "Mg"$ atoms is

$3.543 × cancel(10^23\ "atoms") × (1 cancel"mol")/(6.022 × cancel(10^23\ "atoms")) × 24.3\ "g"/cancel"mol" = "14.3 g"$

0 like 0 dislike
1 views
Talk Doctor Online in Bissoy App
A magnesium atom reacts to produce a magnesium ion. Which diagram shows a magnesium ion?

a magnesium atom reacts to form magnesium ion losing 2 electrons and thus has a +2 charge and 10 electrons .

1 Answers 1 views
A sample of a substance containing only magnesium and chlorine was tested in the laboratory and was found to be composed of 74.5% chlorine by mass. If the total mass of the sample was 190.2 grams, what was the mass of the magnesium?

In a binary compound, $XY$, if $%X$ is given, then, clearly, $%Y=100-X%$ with respect to mass. So we take that figure and multiply it by the mass of the...

1 Answers 1 views
I did a Magnesium Oxide Lab.Magnesium often reacts with nitrogen in the air. If some of the magnesium had reacted with the nitrogen, would it make the % composition of ur sample higher or lower than it should be? Explain (Hint-Try a sample calculation).

Okay, so you've performed the classic magnesium oxide lab. I assume that you have your data, so I'll just walk you through this from a theoretical standpoint. So, you...

1 Answers 1 views
In the gravimetric analysis of magnesium, when combusted to magnesium oxide, why should care be taken to collect all of the magnesium oxide is retained by the crucible?

.....the following reaction occurs. $Mg(s) + 1/2O_2(g) rarr MgO(s)+Delta$ The magnesium oxide is a finely divided white solid, and CAN be lost during the exothermic combustion reaction. Nevertheless, given complete...

1 Answers 1 views
Which option contains a $2*g$ mass of sodium atoms.... $1.$ $5.24xx10^22*"sodium atoms?"$ $2.$ $6.022xx10^24*"sodium atoms?"$ $3.$ $3.12xx10^23*"sodium atoms?"$ $4.$ $5.24xx10^22*"sodium atoms?"$

We know that $1*mol$ contains $6.022xx10^23$ individual sodium atoms, and has a mass of $22.99*g$. And thus for $1.$ there is a $2*g$ mass of $Na$. For $2.$ there is...

1 Answers 1 views
How many nitrate ions, NO3-, and how many oxygen atoms are present in 1.00 microgram of magnesium nitrate, Mg (NO3)2? Also what mass of oxygen is present in 1.00 microgram of magnesium nitrate?

Number of nitrate ions $"Moles of Mg"("NO"_3)_2 = 1.00 × 10^"-6" color(red)(cancel(color(black)("g Mg"("NO"_3)_2))) × ("1 mol Mg"("NO"_3)_2)/(148.31 color(red)(cancel(color(black)("g Mg"("NO"_3)_2)))) = 6.743 × 10^"-9"color(white)(l) "mol Mg"("NO"_3)_2$ $"Moles of NO"_3^"-" = 6.743...

1 Answers 1 views
How do i calculate the number of moles of magnesium, chlorine, and oxygen atoms in 7.70 moles of magnesium perchlorate, $"Mg"("ClO"_4)_2$. Express the number of moles of Mg, Cl, and O atoms numerically, separated by commas. moles of Mg, Cl, O =?

$1 "mol" " Mg"("ClO"_4)_2$ contains :- $color(red)(1 "mol Mg atoms")$ $color(blue)(2 "mol Cl atoms"$ $color(green)(8 "mol O atoms"$ To find no. of moles of each element,...

1 Answers 1 views
A mixture of magnesium carbonate and magnesium oxide of mass $12.46*g$ underwent fierce heating. After heating, there were $8.43*g$ of salt remaining. What were the masses of magnesium carbonate, and magnesium oxide in the original sample?

$MgCO_3(s)+DeltararrMgO(s) + CO_2(g)$ And we would have to heat the magnesium salt VERY fiercely to get complete decarboxylation. $"Moles of carbon dioxide LOST"$ $=$ $(4.40*g)/(44.01*g*mol^-1)$ $=0.010*mol$ And therefore in...

1 Answers 1 views
Calculate the percentages by mass of magnesium, oxygen and hydrogen in magnesium hydroxide, $Mg(OH)_2$. What is the mass of magnesium in $97.4$ $g$ of $Mg(OH)_2$?

The molar mass of $Mg(OH)_2$ is $58.3$ $gmol^-1$. The formula mass contains one mole of $Mg$ $(24.3$ $gmol^-1)$ and two moles each of $O$ $(16$ $gmol^-1)$ and hydrogen $H$ $(1$...

1 Answers 1 views
Magnesium will burn in oxygen to form magnesium oxide as represented by the following equation 2Mg(s) + O2(g) -> 2MgO(s) What mass of magnesium will react with 498.1 ml of oxygen at 145.2 degrees Celsius and 0.927 atm?

We use the Ideal Gas Equation to access the molar quantity of dioxygen gas............ $n=(PV)/(RT)=(0.927*atmxx0.4981*L)/(0.0821*(L*atm)/(K*mol)xx418.4*K)=1.34xx10^-2*mol$. Given the stoichiometric equation.......... $Mg(s) + O_2(g) rarr MgO(s)$ There are $1.34xx10^-2*molxx24.31*g*mol^-1=??*g$ metal required for...

1 Answers 1 views
X