When a $3.0*g$ mass of carbon is burnt in an $8.0*g$ mass of dioxygen, the carbon and the oxygen are stoichiometrically equivalent. Of course, the combustion reaction proceeds according to...
1 Answers 1 viewsAlumina is $Al_2O_3$, which is the product of aluminum oxidation. None of your equations shows the correct formulae. We can rewrite the correct equation as: $2Al(s)+ 3/2O_2(g) rarr Al_2O_3(s)$ This...
1 Answers 1 viewsWe're asked to find the mass of $"CO"_2$ produced in a given reaction, given that $108$ $"g H"_2"O"$ is formed. What we can do first is write the balanced chemical...
1 Answers 1 viewsWe represent the combustion of ethylene by this reaction: $H_2C=CH_2(g) +3O_2(g) rarr 2CO_2(g) + 2H_2O(l)$ For complete combustion, $28*g$ of ethylene thus requires $96*g$ of dioxygen. Here, $"moles of ethylene"$...
1 Answers 1 viewsFrom the equation above, 3 moles of carbon dioxide result from every mole of propane combusted. We had, $(7.51*g)/(44.1*g*mol^-1)$ $=$ $?? "moles of propane"$. So how many moles of...
1 Answers 1 viewsGiven the molecular weights: $Mr_(NaOH)=40 g/(mol)$ $Mr_(Na_2SO_4)=142 g/(mol)$ The analogy of the moles will be held constant: $n_(NaOH)/n_(Na_2SO_4)=2/1$ $n_(NaOH)/n_(Na_2SO_4)=2$ For each one, substitute: $n=m/(Mr)$ Therefore: $n_(NaOH)/n_(Na_2SO_4)=2$ $(m_(NaOH)/(Mr_(NaOH)))/(m_(Na_2SO_4)/(Mr_(Na_2SO_4)))=2$ $(200/40)/(x/142)=2$ $(200*142)/(40x)=2$ $200*142=2*40x$...
1 Answers 1 viewsWhy can I say "clearly"? The stoichiometric equation you have posted shows that 1 mole of ethylene requires 3 moles of oxygen gas (the diatomic molecule). Thus, 2.70 mol ethylene...
1 Answers 1 viewsStart by using the ideal gas equation to figure out the the number of moles $O_2$ used. $ P*V= n*R*T$ Where $P" "$ is the pressure expressed in atm. $V"...
1 Answers 1 views$"8.855 g/L"$ This is just asking you to calculate the new molar (i.e. molar solubility) at a different pressure, i.e. use the . (We'll end up converting...
1 Answers 1 views$"2CO +O"_2rarr"2CO"_2$ $;DeltaH^@=-564*kJ*mol^-1$ $DeltaH^@$ is always quoted per mole of reaction as written. That is synthesis of 2 moles of carbon dioxide from 2 moles of carbon monoxide and...
1 Answers 1 views