To get the atomic mass of an element, we must take a weighted average of the atomic masses of its . That is, we multiply the atomic mass of each...
1 Answers 1 viewsI'm not entirely sure that I understand your question, but the longest wavelength would belong to the red colored light. When an electron drops from energy level 3 to...
1 Answers 1 viewsNote that you were given only one energy state. If you consider two energy states, from $n = 4$ to $n = 1$, we have: $E_1 - E_4 =...
1 Answers 1 viewsWavelength You use the Rydberg formula to calculate the wavelength, λ: $color(blue)(bar(ul(|color(white)(a/a) 1/λ = RZ^2(1/n_2^2 -1/n_1^2)color(white)(a/a)|)))" "$ where $R =$ the Rydberg constant ($1.097 × 10^7color(white)(l)...
1 Answers 1 viewsAnd for this process we use the , $1/lambda_("vacuum")=R{1/(1/n_1^2-1/n_2^2)}$,......... ......where $R="the Rydberg constant,"$ $1.097 xx 10^7 *m^(−1);$ $n_1=2, n_2=5$........ $1/lambda_("vacuum")=1.097xx10^7*m^-1{1/(1/2^2-1/5^2)}$ $1/lambda_("vacuum")=1.097xx10^7*m^-1{1/(1/4-1/25)}=52238095.2*m^-1$ And thus $lambda=8.90xx10^-8*m$, if I have done my...
1 Answers 1 viewsThe energy transition will be equal to $1.55 * 10^(-19)"J"$. So, you know your energy levels to be n = 5 and n = 3. Rydberg's equation will allow...
1 Answers 1 viewsIn order to solve this question we will use the Bohr Model. The change in energy according to Bohr can be calculated by: $DeltaE=-2.178xx10^(-18)Z^(2)J(1/(n_("final")^2)-1/(n_("initial")^2))$ Here, the initial level is $n_("initial")=1$...
1 Answers 1 viewsAs a preface, since you have asked for the "difference in energy", I will give an answer that has no sign. That is, I will give $|DeltaE|$, a magnitude....
1 Answers 1 viewsRelativistic effects are present here... but I assume that the transition from level $a$ to level $g$: has $DeltaL = pm 1$ (the total change in angular momentum is...
1 Answers 1 viewsA is the component of the solution which is present in the greatest quantity. Quantitatively the answer is within the question, substance D will be considered the solvent since it's...
1 Answers 1 views