I have got these in the wrong order by the terms of the question... A $"covalent bond"$ is stronger than an $"ionic bond"$, the which is stronger than an $"hydrogen...
Well, real gases have intermolecular forces, don't they? And thus, we use the van der Waals equation of state to account for such forces: $P = (RT)/(barV...
Van der waals forces or what is also called London Dispersion forces (LDF) increase with the increase of surface area. For example, we know that the only possible intermolecular forces...
Hydrogen includes inter molecular interactions with permanent dipoles (and partial charges) between hydrogen atoms and a few other . are based on random and instantaneous dipoles which last for fractions...
Van der Walls include any kind of inter- or intra-molecular force other than covalent and ionic bonds, including all interactions between: charges and dipoles dipoles and dipoles monopoles and...
As the name suggests, vanderwaal's force is merely a force of attraction b/w two molecules. It occurs when the protons of one molecule attract the electrons of the other....
Van der Waals forces include dipole-dipole forces, dipole-induced dipole forces, and London dispersion forces. Side note: Some people have the misconception that van der Waals forces only include London...
The reason is simple because the ionic bonds are formed due to electrostatic attraction between two atoms hence they are definitely the strongest one. Next comes the covalent bond...
$a = "5.493 L"^2cdot"bar/mol"^2$ $b = "0.06412 L/mol"$ $P = "3.875 bar"$ Using the result derived in full that: $a = (27R^2T_c^2)/(64P_c)$ $b = (RT_c)/(8P_c)$ and the...
The van der Waals (vdW) volume correction and pressure correction terms in $P = (RT)/(barV - b) - a/(barV^2)$ are: $barV_"corr" = barV - b$ $P_"corr" =...
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