Share with your friends
Call

Sulfuric acid is easy: $HO-S(=O)_2(OH)$, we have a $S(VI+)$ oxidation state. Alternatively, I could represent this as $HO-""^(2+)S(-O)_2^(-)(OH)$.

For $"iodous acid"$ I have a formal $I^(III+)$ oxidation state:

$O=I-OH$

This is an unstable beasty, and I don't think it has ever been isolated.

Talk Doctor Online in Bissoy App