Something worth knowing about deciding between nonpolar and polar is that only two of the same element can form an ideally nonpolar bond.
With this in mind, the $"Br"-"Br"$ and $"N"-"N"$ are both nonpolar covalent bonds.
Bonds between a metal and a nonmetal are almost always considered "ionic", so the $"Rb"-"I"$, $"Cs"-"Cl"$, and $"Ca"-"O"$ are all ionic bonds.
And therefore, the remaining binary ($"S"-"I"$, $"O"-"F"$, and $"P"-"I"$), which are those with two nonmetals, form polar covalent bonds, those in which electrons are dispersed unevenly throughout the bond.
In summary,
$color(red)("Rb" + "I"$: ionic
$color(blue)("Br" + "Br"$: nonpolar covalent
$color(green)("S" + "I"$: polar covalent
$color(blue)("N" + "N"$: nonpolar covalent
$color(green)("O" + "F"$: polar covalent
$color(red)("Cs" + "Cl"$: ionic
$color(red)("Ca" + "O"$: ionic
$color(green)("P" + "I"$: polar covalent
