From above, $"Volume"$ $=$ $"Mass"/rho$, for a copper volume of $45$ $cm^3$, we simply multiply by $rho$ to get mass: $"Mass"$ $=$ $rhoxx"volume"$ $=$ $8.920*g*cancel(cm^-3)xx45*cancel(cm^3)$ $=$ $??g$ For the volume...
1 Answers 1 viewsDo you agree? The copper displaces the given volume of water. Now $rho_"Cu"=8.90*g*cm^3$ OR $rho_"Cu"=8.90*g*mL^-1$, i.e. $1*mL-=1*cm^3$ But by definition, $rho_"density"="mass"/"volume"$ And thus $"mass"=rhoxx"volume"=8.90*g*cancel(mL^-1)xx23.4*cancel(mL)$ $=208.3*g$. Do you follow?
1 Answers 1 viewsSo we could oxidize a single atom up to a multi-charged cation......... $Cu+DeltararrCu^(29+) + 29e^-$ Of course we would need a LOT of energy to do this, and so the...
1 Answers 1 viewsDifferent combinations of atoms have different physical properties. For instance, when iron rusts, its melting point lowers.
1 Answers 1 viewsBoth malleability and ductility are prized physical properties of metals. Given these properties, metals are the premier materials for tool making. What is malleability?
1 Answers 1 viewsYou have given the stoichiometric equation that represents reduction of cuprous sulfide: $Cu_2S(s) + O_2(g) rarr 2Cu(s) + SO_2(g)$ Sulfur is oxidized; copper and oxygen are reduced. $"Moles of copper"=(650*g)/(63.55*g*mol^-1)=10.3*mol$....
1 Answers 1 views$CuCO_3(s) + 2HCl(aq)rarrCuCl_2(aq) + CO_2(g)uarr + H_2O(l)$ Or........... $CuO(s) + 2HCl(aq)rarrCuCl_2(aq) + H_2O(l)$ For each acid base reaction the product is the beautiful blue-coloured $[Cu(OH_2)_6]^(2+)$ ion, which is commonly represented...
1 Answers 1 viewsThere is a loss of 0.4 grams. $ 2.0 -1.6$ = 0.4 grams $ 0.4/2.0 xx 100 $ = 20% The Hydrogen will combine with the Oxygen in...
1 Answers 1 viewsThe idea here is that you need to use the mass of copper and the mass of the copper sulfide to determine how much sulfur the produced compound contains, then...
1 Answers 1 viewsThe empirical formulas are $"Cu"_2"O"$ and $"CuO"$. Oxide 1 $color(white)(mmmmml)"Cu" +color(white)(m) "O" → "Oxide 1"$ $"Mass/g":color(white)(l) 2.118color(white)(ll) 0.2666$ Our job is to calculate the ratio of the moles of...
1 Answers 1 views