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When a cutting from a plant sprouts roots and yields a new, independent plant, what process has occurred?
from Wiki Vegetative reproduction (vegetative propagation, vegetative cloning ) is • any form of asexual reproduction occurring in plants • in which a new plant grows...
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A sample of element X contains 100 atoms with a mass of 12.00 and 10 atoms with a mass of 14.00. What is the average atomic mass (in amu) of element X?
The average of an element is calculated by taking the weighted average of the atomic masses of its stable . In other words, each stable isotope will contribute to...
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A fictitious element that has two isotopes has an average atomic mass of 117.3. If 65.43% of the atoms of the element have an atomic mass of 119.8, what is the atomic mass of the other isotope?
The weighted average of the is equal to $117.3*"amu"$. And thus.........with units of $"amu"$ $[65.43%xx119.8+34.57%xxchi] =117.3$ Where $chi-="mass of the other isotope"$.... And so we solve for $chi$.... $chi=(117.3-0.6543xx119.8)/(0.3457)=112.6*"amu"$
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In the ground state, each atom of an element has two valence electrons. This element has a lower first ionization energy than calcium. Where is this element located on the Periodic Table?
It is a period or row that is energy level five or more, below calcium on . Two valence electrons places the element in the alkaline earth family or...
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How do ionization energy and electron affinity determine whether atoms of elements will combine to form ionic compounds?
Let us consider the definitions of ionisation energy and electron affinity for a moment. (First) ionisation energy - The minimum amount of energy required to remove the most...
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1.8 grams of atoms of hydrogen are excited to radiations. the study of spectra indicates that 27% of atoms are in the third energy level and 15% of atoms ate in the second energy level and rest in the ground state. If the I.P. of H is $21.7*10^(-12)$erg?
1. No. of atoms present in second and third energy level (a) Calculate the number of $"H"$ atoms $"No. of H atoms" = 1.8 color(red)(cancel(color(black)("g H"))) × (1 color(red)(cancel(color(black)("mol H"))))/(1.008...
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What is a reaction in which the atoms of element replace the atoms of a second element?
For , the atoms are rearranged so that an element replaces an element in the compound. It usually looks somewhat like this: $AB+C -> AC+B$
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Weight of 50 atoms of an element is 3000 a.m.u. Calculate the number of atoms in 240 grams of element?
$"Mass of 1 atom" = 1 color(red)(cancel(color(black)("atom"))) × "3000 u"/(50 color(red)(cancel(color(black)("atoms")))) = "60.0 u"$ $"Mass of 1 mol of atoms = 60.0 g"$ $"Number of moles" = 240 color(red)(cancel(color(black)("g"))) ×...
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Which option contains a $2*g$ mass of sodium atoms....
$1.$ $5.24xx10^22*"sodium atoms?"$
$2.$ $6.022xx10^24*"sodium atoms?"$
$3.$ $3.12xx10^23*"sodium atoms?"$
$4.$ $5.24xx10^22*"sodium atoms?"$
We know that $1*mol$ contains $6.022xx10^23$ individual sodium atoms, and has a mass of $22.99*g$. And thus for $1.$ there is a $2*g$ mass of $Na$. For $2.$ there is...
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A compound is broken down into 34.5 g of element A, 18.2 g of element B, and 2.6 g of element C. What is the percent (by mass) of each element?
$%A$ $=$ $(34.5*g)/(34.5*g+18.2*g+2.6*g)xx100%=62.3%$ $%B$ $=$ $(18.2*g)/(34.5*g+18.2*g+2.6*g)xx100%=33.0%$ $%C$ $=$ $(2.6*g)/(34.5*g+18.2*g+2.6*g)xx100%=4.70%$ That is $%" element"$ $=$ $"Mass of element"/"Mass of compound"xx100%$ $"Mass of compound"$ is clearly the SUM of the constituent ....
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