None of the atoms in our representation of the $O=C=O$ molecule bear a formal charge. For carbon and oxygen, $Z=6$ and $Z=8$ respectively, i.e. there are 6 and 8 formal...
1 Answers 1 viewsSulfur assumes a $+VI$ oxidation state in the acid anhydride sulfur trioxide, and of course has the same oxidation state in sulfuric acid. $(O=)S^(2+)(-O^-)_2$ Most chemists would settle for...
1 Answers 1 views$CO_2$ taken in by the plant initially bonds to ribulose 1,5-biphosphate or $RuBP$ to form an unstable 6-carbon compound. This then divides into two three-carbon of glycerate 3-phosphate. With the...
1 Answers 1 viewsBy definition there are $6.022xx10^23$ carbon dioxide molecules in a $44.0*g$ mass. How do I know this? Well because we use the given number to specify molar mass, the which...
1 Answers 1 views.......where $N_A="Avogadro's Number"$ $=$ $6.022xx10^23*mol^-1$. And so, $1.70xx10^-2*molxxN_A=1.70xx10^-2*cancel(mol)xx6.022xx10^23*cancel(mol^-1)$, approx. $1.0xx10^22$ $"carbon dioxide molecules"$. We get the answer as a number as required.
1 Answers 1 viewsYou have $3.90xx10^23$ molecules, and the molar quantity is the simply the quotient, $(3.90xx10^23*"molecules")/(6.022xx10^23*"molecules"*mol^-1)$ $=$ $??mol$
1 Answers 1 viewsThe balanced chemical equation tells us unequivocally that 16 g of methane gas reacts with 32 g of dioxygen gas to give 44 g of carbon dioxide, and 36 g...
1 Answers 1 viewsStart by taking a look at the balanced chemical equation for this $"NaOH"_text((aq]) + "HCl"_text((aq]) -> "NaCl"_text((aq]) + "H"_2"O"_text((l])$ Notice that you have $1:1$ between all the...
1 Answers 1 views$10gramsCaCO_3(s) => CaO(s) + (?)O_2(g)$ $"moles" CaCO_3 = ((10g)/(100(g/(mol))))$ = $0.10"mole"$ From reaction ratios => moles $CaCO_3(s)$ consumed = moles $O_2(g)$ produced = 0.10 mole $(O_2(g))$**** If a 'dry'...
1 Answers 1 viewsThe idea here is that you need to figure out how many moles of carbon dioxide, $"CO"_2$, are initially dissolved in the soda by using the volume and of...
1 Answers 1 views