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.......where $N_A="Avogadro's Number"$ $=$ $6.022xx10^23*mol^-1$.

And so, $1.70xx10^-2*molxxN_A=1.70xx10^-2*cancel(mol)xx6.022xx10^23*cancel(mol^-1)$, approx. $1.0xx10^22$ $"carbon dioxide molecules"$. We get the answer as a number as required.

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