The idea here is that each isotope will contribute to the average of the element proportionally to their respective abundance. Now, the key to this problem lies in how you...
1 Answers 1 viewsThe $"Average Atomic Mass"$ of an element is defined as "the weighted average mass of all naturally-occurring (occasionally radioactive) of the element." (and hence the name "average") [1] Dividing the...
1 Answers 1 viewsYou have the one molecule of $CH_4$. How many carbons? How many hydrogens? Both quantities are $>=1$. While I couldn't do this rxn, we could certainly evaluate its thermodynamic parameters:...
1 Answers 1 viewsBalanced Equation $"CH"_4("g") + "H"_2"O(g)"$$rarr$$"CO(g)" + "3H"_2("g")"$ This is a limiting reactant problem. We will determine whether methane or water is the limiting reactant. The limiting reactant will give us...
1 Answers 1 views$"1. Potassium chloride and methane"$, a volatile hydrocarbon, and an ionic solid. NOT MUTUALLY SOLUBLE. $"2. Potassium chloride and carbon tetrachloride"$, another (less) volatile hydrocarbon, and an ionic solid. NO....
1 Answers 1 viewsCan you tell us the molar mass given that carbon has a molar mass of $12.0*g$, and hydrogen, $1.0*g$?
1 Answers 1 viewsTo find the number of moles, all we have to do is use the following relationship: $"Number of moles"$ $=$ $"Mass"/"Molar mass"$ And the molar mass of methane may be...
1 Answers 1 viewsTrying to present a possible Answer We know that the molar mass of carbon and hydrogen are $C=12"g/mol" and H = 1"g/mol"$ When Carbon Hydrogen mass ratio is 11.89 The...
1 Answers 1 viewsStart by determining ratio of $CH_4$ and $H_2$; it can be on these form and use the appropriate ratio depending on your desired unit; $(1 mol CH_4)/(2 mol H_2)$...
1 Answers 1 views$CH_4(g) + 2O_2(g) rarr CO_2(g) + 2H_2O(l)$ The equation explicitly tells us that one equivalent of methane gas reacts with two equiv of dioxygen to give one equiv of carbon...
1 Answers 1 views