The ratio for an mass-to-charge electron is $5.64 x 10^(-12)$ kg/C. In another experiment, using Millikan's oil drop apparatus, the found the charge on the electron is $1.605 x 10^(-19)$ C. What would be the mass of the electron, according to these data?

$rho_"density"$ is given by the quotient.... $rho="mass"/"volume"$...and clearly has associated units of $g*mL^-1$. Here we take the quotient $rho=(43*g)/(50*mL)-=??*g*mL^-1$.. And so would the oil float on water? Why or why...

The elements in this group are not found freely in nature (only in the minutest traces), primarily due to their high reactivity. They readily lose their loosely-bound outer electron to...

well...if you use your data you get: $1.76xx10^8=(1.6xx10^-19)/m$ so $m=(1.6xx10^-19)/(1.76xx10^8)=9.1xx10^-28g$

The experiment is famous, and provided a means to measure electronic charge. Millikan and his students must have been consummate experimentalists, and he was able to show that the electric...

It didn't. J. J. Thomson discovered the electron in 1897. He calculated the charge-to-mass ($e$/$m$) ratio of the electron. In 1904, he proposed the plum pudding model, in which the...

Robert Millikan won the 1923 Nobel Prize in Physics partly for the oil drop experiment. The official citation stated that he received the prize "for his work on the elementary...

Millikan and Fletcher calculated that the charge of the electron was 1.5924 × 10⁻¹⁹ C. See . Their value differed from the currently accepted value of 1.602 176 487 ×10⁻¹⁹...

Millikan's experiment was a triumph of data collection, and experimental design...but it really did not add too much to theory. Before Millikan's time, the mass to charge ratio of the...

There was no big surprise in . The big surprise came in his earlier experiments. Here's the story. In 1896, J.J. Thomson had shown that all cathode rays have a...

Trying to present a possible Answer We know that the molar mass of carbon and hydrogen are $C=12"g/mol" and H = 1"g/mol"$ When Carbon Hydrogen mass ratio is 11.89 The...