The question is not clear but I think this is likely what you are looking for. If $2/3$ of the block of wood is submerged then $color(white)("XXX")$the mass of water...
1 Answers 1 viewsIn a molecular compound, there is little intermolecular force between molecules. Gases, certainly molecular materials, in which the space between molecules is vast, are inherently LOW materials. On the other...
1 Answers 1 viewsSome do not exist as individual molecules. For example, there is no such thing as a molecule of sodium chloride. That's why it is appropriate to use the term formula...
1 Answers 1 viewsAs you know this salt is commonly used to treat mania. The formula mass is simply the sum of the molar masses of the contributing atoms: i.e. $(2xx6.94+12.011+3xx15.999)*g*mol^-1$ $=$ $??$
1 Answers 1 viewsWeight of $Ca$ = $40$ Weight of $Cl$ = $35.5$ Molecular formula is $CaCl_2$ i.e. $1$ atom of $Ca$ and $2$ atoms of $Cl$. Hence, molecular weight = $"1...
1 Answers 1 viewsLet the percentage of the isotope $""^71Ga$ be $=x%$ Then, The percentage of the isotope $""^69Ga$ is $=(100-x)%$ We write the mass balance equation $100*69.72=x*71+(100-x)*69$ $6972=71x+6900-69x$ $2x=6972-6900=72$ $x=36$ Therefore, The...
1 Answers 1 viewsThe distinction between a molecular and non-molecular structure is one of the most important criteria with which to assess . But here, if we have an elemental molecule, we have...
1 Answers 1 viewsAs always with these problems, it is useful to assume $100*g$ of unknown compound....and thus find an empirical formula... $"Moles of carbon"=(12.8*g)/(12.011*g*mol^-1)=1.066*mol.$ $"Moles of hydrogen"=(2.1*g)/(1.00794*g*mol^-1)=2.084*mol.$ $"Moles of bromine"=(85.1*g)/(79.90*g*mol^-1)=1.066*mol.$ And we...
1 Answers 1 viewsFirst, you want to find the ratio between the empirical formula and molecular formula; that is, how much has the molecular formula been simplified to reach the empirical formula. We...
1 Answers 1 viewsStart with the balanced chemical equation for the of potassium chlorate, $KClO_3$ $color(green)(2)KClO_(3(s)) stackrel(color(red)("heat"))(->) color(blue)(2)KCl_((s)) + color(orange)(3)O_(2(g))$ The important thing to notice here is that $color(green)(2)$ moles of potassium chlorate...
1 Answers 1 views