The question is not clear but I think this is likely what you are looking for.
If $2/3$ of the block of wood is submerged then $color(white)("XXX")$the mass of water displaced by $2/3$ of the volume of the block of wood is equal to the mass of the block of wood.
Another way to say this is: each unit volume of wood can be supported by $2/3$ of a unit volume of water.
$(1/2)^(t/5730)(I)=A$ I = initial amount, A = current amount, t = years I=0.200g, A= 0.0125g, solve for t $(1/2)^(t/5730)(0.200)=0.0125$ $(1/2)^(t/5730)=0.625$ $log_(1/2)((1/2)^(t/5730))=log_(1/2)0.0625$ $t/5730=4$ $t=22920$
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