Half life is the time required for half of the original $""^14"C"$ in the sample to decay into $""^14"N"$ through beta decay. The way that $""^14"C"$ dating works is as...
The half life of $C-14$ is $t_(1/2)=5730y$ The radioactive constant is $lambda=ln2/t_(1/2)=ln2/5730=1.21*10^-4y^-1$ Apply the equation $m(t)=m_0e^(lambdat)$ $(m(t))/m_0=e^(lambdat)$ $lambdat=ln((m(t))/m_0)$ $t=1/lambdaln((m(t))/m_0)$ The time is $t=1/(1.21*10^-4)*ln(0.7)=2948.5y$
The equation for half life is: $N(t) = N(0) * 0.5^(t/(T))$ In which $N(0)$ is the number of atoms you start with, and $N(t)$ the number of atoms left after...
Based on the given information, you would set up the following equation: $(1/2)^x = 0.595$ Then, you would find x: $log ("base 0.595") 1/2 = x$ $x =...
The half-life of carbon-14 is $5730$ years. Therefore, after $1$ half-life there is $50%=1/2$ of the original amount left. $2$ half-lives there is $25%=1/4$ of the original amount left. $3$...
The half life of carbon-$14$ is $t_(1/2)=5730y$ This means that in $5730y$, the initial amount of carbon$-14$ will be halved The radioactive constant is $lambda=ln2/t_(1/2)=ln2/5730=0.000121$ The fundamental decay equation is...
The wood will float if it has less than the water. Density is defined by mass per volume, therefore we just need to find the volume of the wood since...
The density of a substance can be calculated using: $d=m/V$ where $m$ is the mass, and $V$ is the volume. Here we do not have the volume given, however...
These figures are from the Wikipedia entry on Carbon-14. The value has been calculated by correlating $""^14"C"$ / $""^12"C"$ ratios with other indicators of age such as comparing tree-ring dates...
