$69%$ for the that weighs 62.93 u and $31%$ for the that weighs 64.93 u.
You can approach this problem by using a single equation; let's say the first isotope contributes to the relative by a fraction $x$ ($x<1$). SInce there are only 2 to consider, the fraction the other isotope contributes with will automatically be $1-x$.
Let's set up the equation
$x * 62.93u + (1-x) * 64.93u = 63.55u$
Solving this for $x$ will produce
$64.93u - 63.55u = 2x -> x = 1.38/2 = 0.69$
Multiplying these fractions (0.69 and 1 - 0.69 = 0.31) by 100% percent to get the results as a percentage will give
$69%$ for the isotpe that weighs 62.93u and
$31%$ for the one that weighs 64.93u.