The atomic weight of a newly discovered e ement is 98.225 amu. It has two naturally occuring isotopes. One isotope has a mass of 96.780 amu. The second isotope has a percent abundance of 41.7%. What is the mass of the second isotope?

Md Ariful Islam

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Md Ariful Islam

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$M_r=(sum(M_ia))/a$, where:

  • $M_r$ = relative attomic mass ($g$ $mol^-1$)
  • $M_i$ = mass of each isotope ($g$ $mol^-1$)
  • $a$ = abundance, either given as a percent or amount of $g$

$98.225=(96.780(100-41.7)+M_i(41.7))/100$

$M_i=(98.225(100)-96.780(58.3))/41.7=100.245"amu"$

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