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And thus there are 4 nuclear protons; and if there are 4 positive nuclear charges there must be 4 negative electronic charges, supplied by 4 electrons. Now the common isotope is $""^9Be$, which means that commonly, the element contains 5 massive, NEUTRAL particles, 5 neutrons. The atomic mass of the nuclide is, as always, THE SUM of the $"the sum of the noocoolar particles"$ to a good first approximation.

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