To an excellent approximation, is equivalent to nuclear mass; i.e. the combined mass of neutrons and protons. Can you tell us the identity of the nuclide? You have all the info necessary to do so.
The most important thing to keep in mind here is that are atoms that have the same number of protons inside their nuclei. In other words, an isotope...
And $Z$ defines the identity of the element: $Z=1,H;Z=2,He;..........Z=6,C;........Z=37, Ru...........$ You don't have to remember these numbers, because a Periodic Table will be supplied to you in every test of...
The $"Average Atomic Mass"$ of an element is defined as "the weighted average mass of all naturally-occurring (occasionally radioactive) of the element." (and hence the name "average") [1] Dividing the...
The average isotopic mass is the weighted average of the mass of the individual . Because the quoted average, $63.6$ $"amu"$, is closer to $""^63A$ than $""^65A$, the $""^63A$...
The weighted average of the is equal to $117.3*"amu"$. And thus.........with units of $"amu"$ $[65.43%xx119.8+34.57%xxchi] =117.3$ Where $chi-="mass of the other isotope"$.... And so we solve for $chi$.... $chi=(117.3-0.6543xx119.8)/(0.3457)=112.6*"amu"$
There are few simple rules to follow. (1) The is equal to the number of protons. $Z$ = number of protons (2) In neutrally charged , the number of electrons...
$Z$, $"the atomic number"$ of magnesium is 12. This means that there are 12 positively charged nuclear particles. This defines the particle as a magnesium atom. To represent the $""^24Mg$...
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