A cube made of an unknown material has a height of 9 cm. The mass of this cube is 3,645 grams. How do you calculate the density of this cube given this information?

The radius= 1.08cm = 0.43in $density=(mass)/(volume)$ $Volume = (mass)/(density)$ $Volume=(82)/(2.7)=30.37cm^3$ The volume of a sphere is given by: $V =4/3pir^3$ So $ r^3=(3V)/(4pi) =(3xx30.37)/(4xx3.142)=1.274$ $r = 1.084cm$

So we need to find a metal with $rho=2.70*g*cm^-3$. Obviously, we don't know these off the tops of our heads. We look for an elemental metal only, because clearly, we...

The thing to remember about is that its purpose is to express the mass of one unit of volume of a given substance. In other words, in order...

Can you tell me how much water you have if I tell you its is $"0.998 g/mL"$? (No. You could have a droplet... or several oceans. They'll all have densities...

$rho, "density"="mass"/"volume"=(21.6*g)/(8.0*cm^3)=??*g*cm^-3$. And I all have done is simply taken the appropriate quotient. Would this float on water? What is the in $g*mL^-1$?

By definition, $rho="Mass"/"Volume"=(80*g)/(4*cm^3)=(80*g)/(64*cm^3)$ $=5/4*g*cm^-3.................$ Would the cube float on water?

You know that the sample is shaped as a rectangular cube, i.e. a rectangular prism, which means that you can determine its volume by using the equation $color(blue)(ul(color(black)(V...

The idea here is that the of the gas tells you the mass of this gas that occupies exactly $"1 L"$ at some unspecified conditions for pressure and temperature....

is equal to mass divided by volume. You are given a mass of $64.7$ grams. You can find the volume of the cube by doing height multiplied by width...

The most important thing to realize here is that since the is a liquid, you must be dealing with a , which as you know does not ionize in aqueous...